Equations with multiple absolute value operators

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Homework Help Overview

The discussion revolves around solving inequalities involving multiple absolute value operators, specifically the inequality |x + 2| - |x| > 1. Participants are exploring how to approach the problem conceptually and mathematically.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to analyze the inequality by checking positive scenarios and expresses difficulty in arranging the equations for negative scenarios. Some participants suggest rewriting the inequality and considering different intervals to handle the absolute values.

Discussion Status

Participants are actively engaging with the problem, exploring various methods to approach the inequality. There is an acknowledgment of different cases based on the intervals of x, and some guidance has been offered regarding the use of absolute value definitions.

Contextual Notes

There is a mention of needing to consider multiple intervals to fully address the inequality, indicating that the problem may involve different cases based on the value of x.

pinsky
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Hello there. I'm having some problems with absolute values when they contain multiple "abs" operators and some other numbers outside the "abs"-es.

For example:

\left | x+2 \right | - \left | x \right | > 1

If i check it for the positive scenario, the result is true for all x-es.

x+2 - x > 1

I can't conceptually see how to arrange the equations for the second scenario.

I've tried the following

-x-2 < 1 + x

but that didn't give the right result. The correct result is -1/2<x
 
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pinsky said:
Hello there. I'm having some problems with absolute values when they contain multiple "abs" operators and some other numbers outside the "abs"-es.

For example:

\left | x+2 \right | - \left | x \right | &gt; 1

If i check it for the positive scenario, the result is true for all x-es.

x+2 - x &gt; 1

I can't conceptually see how to arrange the equations for the second scenario.

I've tried the following

-x-2 &lt; 1 + x

but that didn't give the right result. The correct result is -1/2<x

I would write the inequality as |x + 2| > |x| + 1.

You can get rid of the absolute values by looking at three separate intervals: -2 < x, -2 < x < 0, and x > 0. Each of these intervals defines one case. The final answer will be the union of the solution sets for the three cases.
 
So is that the general way of doing it?

It seams a bit like a non analytical method :P
 
This technique uses the definition of the absolute value, so there's nothing non-analytical about it.
 
Very well.

Thank you for helping.

SOLVED
 

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