Equilateral Triangles and Complex Variables: Proving the Relationship

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Homework Help Overview

The discussion revolves around proving a relationship involving complex variables, specifically that three complex numbers with equal magnitudes form the vertices of an equilateral triangle if and only if their sum equals zero.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to understand the proof by starting with the condition of equal magnitudes and exploring the implications of the distances between the complex numbers. Some participants suggest manipulating the equation to simplify the problem, while others question the necessity of proving the uniqueness of the equilateral triangle configuration.

Discussion Status

Participants are actively engaging with the problem, offering hints and discussing the implications of their approaches. There is a recognition of the need for further proof regarding the uniqueness of the triangle configuration, indicating a productive exploration of the topic.

Contextual Notes

Some participants note the potential need for additional proofs or clarifications regarding the geometric properties of the complex numbers involved, as well as the implications of their relationships.

nicksauce
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Homework Statement


Let {z1,z2,z3} be complex variables such that |z1| = |z2| = |z3|. Prove that z1,z2,z3 are vertices of an equilateral triangle iff z1 + z2 + z3 = 0.


Homework Equations





The Attempt at a Solution


Not really sure where to start on this. I know that |z2-z1= |z3-z2| = |z3-z1|, but this information didn't get me very far. Any hints on how I should start this proof, or what other information I will need?
 
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Divide your equation by z1. Now you have 1+z2/z1+z3/z1=0. So you can just work with the case 1+y1+y2=0 and |y1|=1 and |y2|=1. Does that make it seem easier?
 
Thanks that was quite helpful. Just one thing though... in the proof I needed to say that there exists just one equilateral triangle with (1,0) as a vertex, and has all the sides length 1 away from the origin. Is this as obvious as it intuitively seems to me, or do you think I should try to prove it?
 
nicksauce said:
Thanks that was quite helpful. Just one thing though... in the proof I needed to say that there exists just one equilateral triangle with (1,0) as a vertex, and has all the sides length 1 away from the origin. Is this as obvious as it intuitively seems to me, or do you think I should try to prove it?

It may seem obvious, but you still have to prove it. If you have 1+y1+y2=0 and |y1|=|y2|=1, look the the real and imaginary parts of y1 and y2. You can actually solve for them.
 

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