Equilibrium applications of Newton's law of motion

Click For Summary

Homework Help Overview

The discussion revolves around the application of Newton's laws of motion in the context of a supertanker moving with constant velocity. Participants are exploring the forces acting on the tanker, specifically the forward thrust generated by its engines and the resistive forces from the water, as well as the buoyant force acting on it.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • The original poster expresses confusion about how to approach the problem, particularly regarding the relationship between thrust, resistive forces, and constant velocity. Some participants suggest breaking the problem into steps and clarify the implications of constant velocity on acceleration and net force.

Discussion Status

Some guidance has been provided regarding the calculation of the resistive force based on the understanding that the net force is zero at constant velocity. The original poster has made progress in solving for the resistive force but is still questioning the relationship between buoyant force and normal force, as well as the necessary parameters for calculating buoyancy.

Contextual Notes

There is a noted lack of information regarding the volume of water displaced, which is relevant for calculating the buoyant force. Participants are navigating assumptions about the forces involved without complete data.

pookisantoki
Messages
44
Reaction score
0
A supertanker with the mass of 1.72 *10^8 kg is moving with a constant velocity. Its engines generate a forward thrust of 5.52*10^4 N. Determine (a) the magnitude of the resistive force exerted on the tanker by the water and (b) the magnitude of the upward buoyant force exerted on the tanker by the water.

I honestly don't know how to do this at all but from the given infor. I thought I could find the sum of forces by M *A but then since it's constant velocity, A would be zero making sume of forces 0. Since it is constant velocity I thought i could use the constant velocity formulas but wasnt sure which one to use since I'm only give mass. I don't even know what kind of force a forward thrust would be considered as... I am so lost please help!
 
Physics news on Phys.org
If you are lost then let's take it in steps.

The engine produces a thrust (force) of 5.52*104 N (FE)

Let's call the resistive force Ff.


So we know the resultant of these two is ma. Now we have an equation ma=FE-Ff.


But we are told the velocity is constant, which tells you that a=0. So can you get the resistive force now?
 
THANK YOU! so I solved it 0=5.52 *10^4-x
x=55200
then for part b. The bouyance force is the force that goes up...would be considered same as normal force? and the answer is the same as the mass * g??
 
pookisantoki said:
THANK YOU! so I solved it 0=5.52 *10^4-x
x=55200
then for part b. The bouyance force is the force that goes up...would be considered same as normal force? and the answer is the same as the mass * g??

I believe that is how it should be done. Although upthrust=weight of fluid displaced = mg =ρVg.

But they didn't give you V=volume of water displaced. So U=mg will work.
 

Similar threads

  • · Replies 25 ·
Replies
25
Views
2K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 23 ·
Replies
23
Views
4K
  • · Replies 17 ·
Replies
17
Views
1K
Replies
9
Views
2K
Replies
6
Views
3K
  • · Replies 31 ·
2
Replies
31
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K