Equilibrium cylinder and plank on incline

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SUMMARY

The discussion centers on a physics problem involving a horizontal stick and a cylinder on an inclined plane, specifically addressing the normal force from the plane on the cylinder and the minimum coefficient of friction (μ) required to prevent slipping. The normal force can be calculated using the mass (m) of the stick and cylinder, the angle of inclination (θ), and the gravitational force. The smallest value of μ is derived from the relationship between the forces acting on the system, ensuring equilibrium. The importance of accurately depicting free body diagrams to avoid errors in calculations is emphasized.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of free body diagrams
  • Familiarity with frictional forces and coefficients
  • Basic concepts of equilibrium in physics
NEXT STEPS
  • Study the derivation of normal forces in inclined planes
  • Learn about static and kinetic friction coefficients
  • Explore advanced free body diagram techniques
  • Investigate applications of equilibrium in real-world scenarios
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the mechanics of systems involving inclined planes and frictional forces.

joemama69
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Homework Statement



A horizontal stick of mass m has its left end attached to a free pivot on a plane (inclined at angle θ), while it’s right end rests on a cylinder also of mass m which in turn rests on the plane, as shown. The coefficient of friction between the cylinder and both the stick and the plane is μ

(a) Assuming that the system is at rest, what is the normal force from the plane on the cylinder?

(b) What is the smallest value of μ (in terms of θ) for which the system doesn’t slip anywhere?


Homework Equations





The Attempt at a Solution



is my free body diagram correct on the attachment. I realize that the Ns and the us are different
 

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Your free body diagram looks okay. I'd be a little more careful to make the normal forces and frictional forces perpendicular and locate them at the points of contact between the surfaces. I'd make mgcos(Q) perpendicular to the inclined plane, but then I'm a fussy old professor. I'd show the attachment of the horizontal stick to the pivot at the end of the inclined plane.

I guess you can summarize it by I'd be a little more complete and a little more careful. You cut down on errors that way. (Plus it impresses the person who grades your homework.)
 
I know this is from a few years ago, but can someone explain to me why that bottom friction force is pointed up the plane. It seems strange...
 

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