- #1
Oomair
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[SOLVED] Equilibrium problem
A uniform beam of mass 76 kg and length 3 m rests on two pivots, one at the left edge and one 2.4 m from the left edge. How far to the right of the right pivot can a mass of 150 kg be placed without the beam tipping?
net forces in y direction, Fy : F1(pivot on egde) - Fg(weight of board) +F1(2nd pivot) - mg
Sum of torque(im torquing around the rigt piovt): F1(2.4m) - Fg(.9m) -mg(x)
the problem I am having is that i have two unknown forces from the pivots, and when i solve for one of the forces, the results cancel out and x = 0, i don't what i am supposed to assume?
Homework Statement
A uniform beam of mass 76 kg and length 3 m rests on two pivots, one at the left edge and one 2.4 m from the left edge. How far to the right of the right pivot can a mass of 150 kg be placed without the beam tipping?
Homework Equations
The Attempt at a Solution
net forces in y direction, Fy : F1(pivot on egde) - Fg(weight of board) +F1(2nd pivot) - mg
Sum of torque(im torquing around the rigt piovt): F1(2.4m) - Fg(.9m) -mg(x)
the problem I am having is that i have two unknown forces from the pivots, and when i solve for one of the forces, the results cancel out and x = 0, i don't what i am supposed to assume?