Equilibrium Problem - Forces acting on beam supports

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SUMMARY

The discussion focuses on calculating the vertical forces acting on two supports of a horizontal beam with a piano placed on it. A 160-kg beam and a 300-kg piano positioned a quarter of the way from one end create a system of forces that must be analyzed. The correct approach involves applying the equilibrium condition ΣFy=0 and taking moments about each support point to determine the forces acting on supports A and B. This method ensures accurate calculations of the vertical forces based on the distribution of weight and distances involved.

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1. A 160-kg horizontal beam is supported at each end. A 300-kg piano rests a quarter of the way from one end. What is the vertical force on each of the supports?



2. Summation of Forces in the y = 0.



3. Going off the above equation, I *think* it would be that ΣFy=0=Fy-Fg-Fp, which would become Fg+Fp=Fy. However, I am not sure if this logic is correct, and I'm unsure where to go from there.

Any help is greatly appreciated!
 
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this question involves moments about a point. so firsty you want to draw a diagram of where all the forces are. so you have two supports (call them A and B) and the mass of beam will be halfway between them (0.5L) and the mass of the piano will be a quater the distance from support A( 0.25L).

now you want to take moments about point A, to find the force acting on support B, and then moments about point B, to find the force acting on support A.
 

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