Equilibrium problem: Multiple forces acting on this hinged, supported beam

Click For Summary
The discussion centers on calculating the resultant force acting on a hinged, supported beam under multiple forces. The user has derived reaction forces at points A and B, confirming equilibrium with a net force of zero. They seek clarification on how to determine a single equivalent force and its point of application, as specified in the problem statement. It is emphasized that if there is no net force but a net moment exists, the moment can be represented independently of the chosen axis. The goal is to replace the external loads with a single force that maintains the same moment about the specified axis.
Racoon5
Messages
6
Reaction score
4
Homework Statement
For Replace the loading acting on the beam by a single resultant force. Specify where the force acts, measured from end A.
Relevant Equations
N/A
Hi, apart from the interesting wording of this question, I'm struggling to understand the concept of what we need to do here.

I started by having three equations (summation Fx, summation Fy and Moment about Y). I also calculated the two reaction forces about A and the one rection force about B (in y direction)

I got Ax= 125 , Ay= 293 and By= 1589
Summed up with all other x and y forces I am getting 0. How do I calculate a resultant force form that?

2. What exactly is asked by the question "specify where the force acts"? I'm assuming its not the angle to the x-axis

Thank you

Screenshot 2024-11-09 at 11.25.08 AM.png
 
Last edited by a moderator:
Physics news on Phys.org
Racoon5 said:
Homework Statement: For Replace the loading acting on the beam by a single resultant force. Specify where the force acts, measured from end A.
Relevant Equations: N/A

Hi, apart from the interesting wording of this question, I'm struggling to understand the concept of what we need to do here.
They want you to replace the external loads with a single equivalent loading (as far as I can tell).
 
Last edited:
You are not being asked to find any reaction forces, though that may come later.

Given any collection of forces and moments acting on a body, and a specified axis, there is a resultant force and a resultant moment about that axis.

If there is no net force but there is a net moment, that moment is independent of the choice of axis.

If there is a net force, you can specify a line of action for it such that it has the same moment about the chosen axis as the resultant moment. In this way, you can completely represent the original collection of forces and moments by a single force applied at a certain point.
 
  • Like
Likes PhDeezNutz, Lnewqban and erobz
Racoon5 said:
I got Ax= 125 , Ay= 293 and By= 1589
Summed up with all other x and y forces I am getting 0. How do I calculate a resultant force form that?
Evidently, the system is in equilibrium regarding net forces and moments.
The isolated beam is under stress caused by external forces and moments.

Like a common spring, it is getting slightly deformed up to the point of inducing internal forces that compensate the external disturbance.
Could those external forces and moments be replaced with a single force acting along certain line?
 
Thread 'Chain falling out of a horizontal tube onto a table'
My attempt: Initial total M.E = PE of hanging part + PE of part of chain in the tube. I've considered the table as to be at zero of PE. PE of hanging part = ##\frac{1}{2} \frac{m}{l}gh^{2}##. PE of part in the tube = ##\frac{m}{l}(l - h)gh##. Final ME = ##\frac{1}{2}\frac{m}{l}gh^{2}## + ##\frac{1}{2}\frac{m}{l}hv^{2}##. Since Initial ME = Final ME. Therefore, ##\frac{1}{2}\frac{m}{l}hv^{2}## = ##\frac{m}{l}(l-h)gh##. Solving this gives: ## v = \sqrt{2g(l-h)}##. But the answer in the book...

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
Replies
1
Views
5K
Replies
10
Views
3K
Replies
6
Views
2K
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
4
Views
2K
Replies
3
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K