The discussion revolves around solving an equilibrium problem where the coefficient of friction, μ(min), is determined to be 1. The key equations involved are the summation of forces in both x and y directions, as well as the summation of torques equating to zero. The friction force remains constant at 4N, and slipping occurs when the static friction maximum (μR) drops below this value. The critical point of slipping is identified at the locations A, B, or C as μ is decreased.
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kuruman said:You have already seen that the force of friction is the same 4N at all points. That's what's required to keep the system at equilibrium. Imagine starting with a large μ and reducing it gradually. Slipping will occur at the point where the maximum value that static friction can have (=μ R) goes just below the value 4 N first. So if you write
μR = 4 N,
at which of the three points A, B and C μR falls below 4 N first as you make μ smaller?