- #1
rtareen
- 162
- 32
- Homework Statement
- You hold a 6.0-kg weight in your hand with your forearm making a 90° angle with your
upper arm, as shown in Figure 12-4. Your biceps muscle exerts an upward force Fm that acts 3.4 cm from the pivot point O at the elbow joint. Model the forearm and hand as a 30.0-cm- long uniform rod with a mass of 1.0 kg. (a) Find the magnitude of Fm if the distance from the weight to the pivot point (elbow joint) is 30 cm, and (b) find the magnitude and direction of the force exerted on the elbow joint by the upper arm
- Relevant Equations
- ## \Sigma \Vec{\Tau }= 0##
##\Signma \Vec{\F} = 0 ##
My initial response to seeing the figure is what is ##F_{ua}## and where does it come from? How was i supposed to know it was there is they didn't give a picture?
So for part a, ##F_{ua}## doesn't play a role because it exerts no torque, and apparently we are supposed to use the torque equation to find ##F_m##. Thats probably the only way to do this problem is to use the torque equation first, because if we used the force equations, we'd have two equations and three unknowns, I think. We would have to solve for the y component of ##F_m## and also both components of ##F_{ua}##. But if there is another way to solve this problem please let me know.
So we can set ##\Sigma \Tau = 0 ## to find ##F_m## and we find that it is 560N. Then we can set the x and y components of force equal to zero and we find out that the x component of ##F_{ua}## is 0. That must mean that ##F_{ua}## is vertical only. And we find out that its 490 N downwards.
My main question is how was i supposed to know about ##F_{ua}##.
Also there is this concept where you can set the net torque to be zero about any point on the object of interest, not just at O. Can someone explain how we could do that? These static equilibrium problems are hard.
Also in the preview my latex code isn't being converted. Can someone tell me why?