Equivalent Capacitance or Resistance and Kirchoff's rules

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Homework Help Overview

The discussion revolves around determining the new equivalent RC circuit when capacitors are filled with a dielectric material. The original poster is uncertain about the meaning of "new equivalent RC circuit" and seeks clarification on the problem's requirements.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants explore the need to find component values for an equivalent circuit with one resistor and one capacitor. There is discussion about total resistance and capacitance, with attempts to express the resulting capacitance in terms of the original values.

Discussion Status

Participants are actively engaging with the problem, with some suggesting specific equations for total resistance and capacitance. There is a mix of interpretations regarding the addition of capacitors in series and parallel, with some seeking confirmation of their understanding.

Contextual Notes

There is a lack of information regarding the area and distance of the capacitors, which is noted as a constraint in expressing the resulting capacitance. Participants are working within the framework of the problem without resolving these uncertainties.

lookingforhlp
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Homework Statement


If each capacitor is filled with a dielectric material (with constant K, kappa), what is the new equivalent RC circuit? All resistors have equal value, and capacitors have equal value (without a dielectric), C.

Homework Equations


C = (Epsilon * Area) / Distance
C with a dielectric is = KC

V=IR

Q=CV

all the resistor and capacitance equivalent equations


The Attempt at a Solution


(Please see attached image for the RC Circuit)

I guess that it's asking for the current? Not sure what "new equivalent RC circuit" means.

I need to know what this is asking before I try it...anyone have any ideas?
 

Attachments

  • RC Circuit.png
    RC Circuit.png
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I presume that they want you to find the component values for an equivalent circuit having just one resistor and one capacitor.
 
So just the total resistance and total capacitance?
 
In that case Rtot = 2R and Ctot = 4K*epsilon*area/distance
 
You're given the original capacitor values, C. You're not given area or distance. So express the resulting capacitance in terms of C.
 
Ctot = 4KC?
 
Sure.
 
lookingforhlp said:
Ctot = 4KC?

Capacitors in series add up, but in parallel they actually reduce the total capacitance. The equation should be easily found in your book.

Someone please correct if I am wrong.
 
I was pretty sure it was the other way around...let me double check
 
  • #10
Capacitors in parallel add directly.
 
  • #11
I agree
 

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