Equivalent circuits resistor problem

1. Sep 7, 2011

DrummingAtom

1. The problem statement, all variables and given/known data

Find Req.

2. Relevant equations

Series: R1 + R2 + ...

Parallel: 1/(1/R1 + 1/R2 + ...)

3. The attempt at a solution

There's no solution for this one in the book but I'm thinking that I can break this up into two parallel sets. Parallel1 = (R1*R4)/(R1 + R4) and Parallel2 = (R3*R2)/(R3 + R2). Is that correct?

Attached Files:

• CircuitsProblem.jpg
File size:
39.3 KB
Views:
235
Last edited: Sep 7, 2011
2. Sep 7, 2011

NewtonianAlch

It's not exactly very easy figuring out that diagram, why not do it properly on paint and then upload the image?

3. Sep 7, 2011

DrummingAtom

Yeah it didn't keep the white space. Sorry

4. Sep 7, 2011

Integral

Staff Emeritus

What is inbetween the right end of R4 and the bottom end of R1?

5. Sep 7, 2011

DrummingAtom

The same voltage?

6. Sep 7, 2011

DrummingAtom

Oh wait.. If I combine Parallel2 into the circuit as one unit it will now be in between the right end of R4 and the bottom end of R1.

7. Sep 7, 2011

NewtonianAlch

If you consider R1 and R4 in parallel, it has to be connected to the negative terminal right? What's helping completing the circuit?

8. Sep 7, 2011

Parallel2

9. Sep 7, 2011

NewtonianAlch

http://slimber.com/index.php?image=resistors.g80803 [Broken]

See if that helps you visualize it better

Last edited by a moderator: May 5, 2017
10. Sep 7, 2011

DrummingAtom

Sort of.. If it was drawn like that then would the solution be:

1/(1/R1 + 1/(R4 +R2) + 1/R3) ?

Last edited by a moderator: May 5, 2017