Error Analysis of wall thickness

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Homework Help Overview

The problem involves measuring the wall thickness of a hollow cylinder using vernier calipers, with specific internal and external diameters provided along with their uncertainties. The original poster attempts to calculate the thickness and its associated error, noting a discrepancy with commonly cited results.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the method for calculating the error in wall thickness, with some suggesting a statistical approach that involves dividing the error by √2. Others question the reliability of the sources that provide different error values.

Discussion Status

Participants are exploring different methods for error calculation and discussing the implications of these methods in practical contexts, such as engineering tolerances. There is no explicit consensus on the correct approach, but various perspectives on error analysis are being shared.

Contextual Notes

There is mention of differing interpretations of error calculation methods, particularly between statistical and deterministic approaches, which may affect the final reported uncertainty. The original poster expresses confusion regarding the discrepancy in error values from various sources.

Nikhil Rajagopalan
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Homework Statement


The internal and external diameter of a hollow cylinder are measured with the help of a vernier calipers. Their values are (3.87 ± 0.01) cm and (4.23 ± 0.01) cm respectively. The thickness of the wall of the cylinder is ?

Homework Equations


Thickness of cylinder wall= 1/2 (Outer Diameter - Inner Diameter)
t = 1/2 (Do - Di)

The Attempt at a Solution



for value of t,

t = 1/2 (Do - Di)
t = 1/2(4.23 - 3.87)
t = 1/2(0.36)
t = 0.18

for finding the error in t,
by differentiating on both sides,

Δt = 1/2 (ΔDo - ΔDi)
Δt = 1/2 (0.01 + 0.01)
Δt = 0.01

thickness t ± Δt = 0.18 ± 0.01

most sources show the answer as 0.18 ± 0.02. Kindly help me to figure out the mistake that i made in calculating the error.
 
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Nikhil Rajagopalan said:
most sources show the answer as 0.18 ± 0.02
Sources you regard as reliable?
I agree with your answer.
Many would take a statistical approach. This allows that the two errors will often cancel out somewhat, and rarely be at opposite extremes. So they would divide the error by √2. But when you need to be sure that engineering tolerances are met, the simple method you used is appropriate.
 
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Likes   Reactions: Jamison Lahman and berkeman
The formula for finding error in the case of ##t=au+bv## where a and b are constants is:
$$\sigma_t = \sqrt{(a\sigma_u)^2+(b\sigma_v)^2}$$
since a and b both equal 1/2 and both ##\sigma_u## and ##\sigma_v## equal 0.01, this nicely simplifies to:
$$\sigma_t = \sqrt{2(1/2(0.01))^2} = \frac{0.01}{\sqrt{2}}$$
So I would agree with @haruspex
 
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Jamison Lahman said:
So I would agree with @haruspex
As I wrote, the approach should depend on the purpose. In manufacturing, the engineer sets tolerances for each component. Each machinist works to those specifications. If the resulting components don't fit the engineer is in trouble.
 
haruspex said:
As I wrote, the approach should depend on the purpose. In manufacturing, the engineer sets tolerances for each component. Each machinist works to those specifications. If the resulting components don't fit the engineer is in trouble.
True, but if you'd like to take the statistical approach as you suggested many would in your first post, that's the rationale behind the root 2. The equation is directly out of Bevington and Robinson (2003).
 

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