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**1. Homework Statement**

Let

*t*=

*f*(

*g*,

*h*,

*A*, Δ

*m*,

*Γ*,

*r*). For

*t*= 2 s, the propagated error is

*σ*= 0.02 s.

Can the error of 1/

*t*

^{2}be simply determined using the known error in

*t*= (2 ± 0.02) s, or must the variance formula (with all the partial derivatives and errors of each dependent variable) be re-derived?

**2. Homework Equations**

When squaring a quantity with an error, the new %error of the square is half the old %error.

I don't know how to find the inverse of an error (tried looking it up online but can't seem to find it).

**3. The Attempt at a Solution**

*t*

^{2}= (2

^{2}± 1% / 2) s = (4 ± 0.5%) s

1/

*t*

^{2}= ?

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