Escape Speed Calculation for Identical Planets

  • Thread starter Thread starter zhen
  • Start date Start date
  • Tags Tags
    Escape Speed
Click For Summary
SUMMARY

The escape speed for a rocket launched from the midpoint between two identical planets, each with mass M and radius R, spaced 6R apart, is not zero. The gravitational potential energy (GPE) must be calculated to determine the escape speed accurately. Using the energy conservation law, the total GPE required to move the rocket from infinity to the midpoint is derived from the equation (GMm/R). This GPE is then equated to (1/2)mv^2 to solve for the escape speed, v.

PREREQUISITES
  • Understanding of gravitational potential energy (GPE)
  • Familiarity with the conservation of energy principle
  • Knowledge of basic physics equations, specifically (GMm/R) and (1/2)mv^2
  • Concept of escape velocity in astrophysics
NEXT STEPS
  • Research the derivation of escape velocity formulas in astrophysics
  • Study gravitational potential energy calculations for multiple bodies
  • Explore the implications of gravitational interactions between celestial bodies
  • Learn about energy conservation in non-uniform gravitational fields
USEFUL FOR

Students and professionals in physics, astrophysics enthusiasts, and anyone interested in celestial mechanics and gravitational calculations.

zhen
Messages
48
Reaction score
0
the question is : there are two identical planets of mass M and radius R spaced 6R apart. What is the escape speed of a rocket launched from the mid-point (3R) between two planets?

I use the energe conservation law. K1 + Ua1 + Ub1 =K2 + Ua2 + Ub2 = 0 to get the Vi
because the rocket is in the middle, the U1 and U2 should be opposite sign, which will cancel out each other. In this case the escape speed should be 0, why that is not true?
 
Physics news on Phys.org
You need to calculate the difference in total gravitational potential between the starting point and infinity. It's not zero.
 
The way I would do it is calculate the total GPE that is required to bring the rocket from infinity to that point, using the equation (GMm/R)... assuming the rocket has no KE to begin with, I would equate (1/2)mv^2 with the resulting expression and solve for v. That's how I would do it.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
5K
Replies
11
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
14K
Replies
4
Views
27K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
2
Views
6K
Replies
15
Views
3K
  • · Replies 9 ·
Replies
9
Views
5K