Gravitational Potential Energy of a rocket

Click For Summary

Homework Help Overview

The discussion revolves around the gravitational potential energy of a rocket launched from the Earth's surface and its speed when it is far away from the Earth. The subject area includes concepts of energy conservation and gravitational potential energy in the context of classical mechanics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of the conservation of energy principle, questioning the assumptions made regarding potential energy at different distances. There are attempts to manipulate the energy equations, with some participants pointing out potential errors in algebra and variable definitions.

Discussion Status

The discussion is active, with participants providing guidance on checking algebraic manipulations and clarifying the definitions of variables used in the equations. There is no explicit consensus yet, as participants are exploring different interpretations of the energy equations and their implications.

Contextual Notes

Some participants question the assumption that potential energy becomes zero at a far distance, and there is discussion about the correct application of the radius of the Earth in the equations. The original poster expresses uncertainty about their calculations and potential issues with their calculator.

mcnealymt
Messages
35
Reaction score
0

Homework Statement


A rocket is launched straight up from the Earth's surface at a speed of 1.80×104m/s . What is its speed when it is very far away from the earth? Answer in m/s

Homework Equations


K1+U1=K2+U2

The Attempt at a Solution



.5mV1^2-(G*m*Me)/r= .5mV2^2-(G*m*Me)/r
*** THe mass of the rocket should cancel out and the U1 aka (g*m*Me)/r should be zero.

you are left with:

.5V1^2=.5V2^2-(G*m*Me)/r
*** Now solve for V1

V1 = Square root of [ (.5V1^2+(GMe)/r)/.5 ]

I got 1.06 *10^4

what am I doing wrong? I know that you have to use conservation of energy and assume that since the rocket is traveling a very far distance the final potential energy is going to be zero. Could it be calculator issues?!
 
Physics news on Phys.org
mcnealymt said:
.5V1^2=.5V2^2-(G*m*Me)/r
*** Now solve for V1

V1 = Square root of [ (.5V1^2+(GMe)/r)/.5 ]
Watch the signs, and I think you meant V2 instead of V1 in the square root. I'm assuming that you are letting "1" stand for final and "2" for initial.
 
Why did you say U1 = 0? It's not.
Then: what is U2?
 
Your original equation is correct, but your implementation of it is incorrect. The r that goes along with V1 is the radius of the earth, and the r that goes along with V2 is infinite. Also, you need to check over your algebra...you have a problem with those 0.5's.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 43 ·
2
Replies
43
Views
4K
Replies
15
Views
2K
Replies
8
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
5
Views
3K
  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 5 ·
Replies
5
Views
1K
Replies
55
Views
6K