There's something bothering me about the event horizons of black holes. The Schwarzchild radius (as I see it) is basically the distance from a center of mass at which the escape velocity is the speed of light. The way escape velocity is defined though is the speed a body must have to "reach infinity," or leave the gravitational field, from a given radius in the proximity of a gravitating body. Couldn't a photon at or inside the event horizon leave the vicinity (say to a nearby galaxy) with corresponding red shift, then "re-gravitate" to the black hole? The red shift equation says a photon emitted from the Schwarzchild radius will be infinitely red-shifted at infinite distance (as r->inf), but it doesn't have to travel to infinity to be observed or absorbed. Am I thinking of this to classically? Do photons not make elliptical orbits in gravitational fields like planets?(adsbygoogle = window.adsbygoogle || []).push({});

Thanks

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Escaping the Schwarzchild Radius

Loading...

Similar Threads for Escaping Schwarzchild Radius |
---|

B Light (not) escaping from black holes |

I Coordinate singularity at Schwarzschild radius |

B Escape velocity from relativistic sphere |

**Physics Forums | Science Articles, Homework Help, Discussion**