Estimate ∫γ dz/(1 + z^4) as R→∞.

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SUMMARY

The integral estimate for ∫γ dz/(1 + z^4) as R approaches infinity is evaluated using the substitution z = Re^(it) for t in [0, π]. The modulus of the integral is bounded by πR / (R^4 - 1), confirming that the integral approaches zero as R increases. The discussion clarifies the misunderstanding regarding the modulus of complex numbers, specifically that |iRe^(it)| equals R, not iRe^(it) itself. This distinction is crucial for correctly interpreting the behavior of the integral at infinity.

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Homework Statement



Estimate ∫γ dz/(1 + z^4) as R→∞.

Note that letting z = Re^(it) for t in [0, π]:
|∫γ dz/(1 + z^4)|
= |∫(t = 0 to π) (iRe^(it) dt) / (1 + R^4 e^(4it))|
≤ ∫(t = 0 to π) R dt / |1 + R^4 e^(4it)|
≤ ∫(t = 0 to π) R dt / (R^4 - 1), since R > 1
≤ πR / (R^4 - 1).

but why does iRexp(it)=R ?
why does i exp(it)=1?
please help
 
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IT never says that [itex]iRe^{it}=R[/itex]. What you use is that the modulus of that is R. Thus

[tex]|iRe^{it}|=|i||R||e^{it}|=1[/tex]
 

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