Estimate the voltage you need with this appartus to ionize the atom

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SUMMARY

The discussion focuses on estimating the voltage required to ionize a hydrogen atom situated between two metal plates 1 mm apart, connected to a 500 V battery. The participants calculate the fraction of the atomic radius represented by the plate separation, concluding it to be approximately 5 x 10-8. They derive the voltage needed for ionization using the dipole moment and electric field equations, ultimately recognizing the limitations of their approach due to the extreme conditions of ionization. The final voltage expression is V = (qd(-E0d/qV))/α, where E0 is the ionization energy of hydrogen at -13.6 eV.

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  • Understanding of atomic structure, specifically the Bohr model of the hydrogen atom.
  • Familiarity with electric fields and dipole moments in physics.
  • Knowledge of ionization energy and its significance in atomic physics.
  • Basic proficiency in algebraic manipulation of physical equations.
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  • Research the relationship between electric fields and dipole moments in more detail.
  • Study the concept of ionization energy and its implications for different elements.
  • Explore the limitations of using dipole approximations in strong electric fields.
  • Investigate alternative methods for calculating ionization potentials in quantum mechanics.
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A hydrogen atom (with Bohr radius of half an angstrom) is situated between 2 metal places 1 mm apart which are connected topoosite terminals of a 500 V battery.
What fraction of the atomic radius does the separation distance d amount to, roughly?

Estimate the voltage you need with this appartus to ionize the atom



For the first part the radius is 5 \times 10^{-11} m[/tex]<br /> the distance between the plates is 0.001 m<br /> divide 5 \times 10^{-11} m/ 0.001 m = 5 \times 10^{-8}<br /> <br /> so far so good, right?<br /> <br /> for the second part... since the atom is polarized it has a tiny dipole moment \vec{p} = \alpha \vec{E}<br /> <br /> p = qd = \alpha \frac{V}{d}<br /> so V = \frac{ q d^2}{\alpha}<br /> <br /> is that correct?? <br /> <br /> thank you for your input!
 
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The argument is not all bad imho, but aren't you confusing the use of symbols here? You haven't defined 'd' in the statement of the problem (:mad: ) but I suspect it is just the distance btw the plates. If we call \vec{\delta} instead the distance caracterizing the dipole moment, we have

\vec{p}=\alpha\vec{E} \Rightarrow q\delta = \alpha E \Rightarrow V=\frac{qd\delta}{\alpha}

and now what? Well we could say that we want V to be such that it induces a dipole moment q\delta such that the work done on the electron in moving a distance \delta parallel to the field is 13.6eV, the ionization energy of the hydrogen atom. So in the end, we need V to be

V=\frac{qd(-E_0d/qV)}{\alpha}

(E_0=-13.6eV)

This argument has a problem though. It is that the proportionality relation btw the field and the induced dipole holds only for weak fields, such that the deformity is not extreme, as it is in this case since we're literally ionizing the thing.

If I were you I would keep thinking for another way of going at this that does not come with such a defect.
 
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im sorry i didnt define d, sorry

well if we're going to ionize an atom (like hydreogen) what is the minimum value of dipole moment :confused: if that exists?
 
How do you mean "minimal value"?

When there is no field, there is no external, there is zero dipole moment, is that what you mean?
 
i can see the problem... but i think they are only caring about small pertubations at least with the tools we are given...
 
ionization is not a small perturbation.

which implies maybe you ought to find a whole other route to the solution.
 

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