Estimated varaince of sample data

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Homework Help Overview

The discussion revolves around calculating the estimated variance of a given sample data set consisting of the values 46, 48, 51, 50, 45, 53, 50, and 48. Participants are exploring different methods for calculating variance and addressing discrepancies in their results.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the formula for variance, specifically questioning the calculation of E(X^2) and the application of the correction factor for estimating population variance. There are inquiries about the correctness of specific calculations and the reasoning behind them.

Discussion Status

The discussion is ongoing, with participants providing feedback on each other's calculations and reasoning. Some guidance has been offered regarding the distinction between calculating sample variance and estimating population variance. There is no explicit consensus on the correct approach yet.

Contextual Notes

Participants are addressing potential errors in calculations and the implications of using different formulas. There is a mention of the importance of clearly typing out formulas to facilitate understanding. Additionally, the original poster has indicated progress in resolving their question.

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Homework Statement


sample data as bellow:
46,48,51,50,45,53,50,48

to find the estimated varaince , the ans with 6.10 is correct... why can't i use this way? my ans for second way is 19051. which is wrong...

Homework Equations

The Attempt at a Solution


Var(x) = E(x^2) -( E(x)^2) = 19159- ( ((391/8) ^2 ) = 16670, then my s^2 = 16670...
i use the top part of the formula ,( 8/ (8-1) ) x 16670 = 19051
 

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In the left shred that you should have retyped under 2. Relevant equations (in which case you would have seen your error) the recipe differs from what you type under

The Attempt at a Solution



(Basically, your <x2> is wrong. )
 
my E(X^2) = 19159... why it's wrong? then what should it be?
 
It should not change by a factor of around 1000 if your sample is a factor 1000 bigger
 
You can compute the variance of the sample - you don't have to estimate it.
Usually your are expected to estimate the variance of the population from the sample.
http://en.wikipedia.org/wiki/Variance#Population_variance_and_sample_variance

However, I cannot tell how you went wrong unless you show your reasoning and calculation.
But it looks like you, at least, have another step to go.
 
somecelxis said:
my E(X^2) = 19159... why it's wrong? then what should it be?

Type out your formulas, so we can see what you are calculating.
 
Type out your formulas, so we can see what you are calculating.
Seconded.
 
Hey guys, let's not all of us be so tough on this guy! He did present something under 3. and I try to point out to him that ##E \ne \Sigma## ...then he's done
 
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As BvU points out, you forgot part of the calculation of E[X2]. The other issue is you have to decide whether you are trying to find the actual variance of the sample or estimate the variance of the underlying population. Only the second involves the n/(n-1) factor.
 
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  • #10
Just for the heck of it, you have a very, very special sample here! Doesn't happen very often that ##<x> = \Sigma (x - <x>)^2 ## exactly !

By the way, is excelsis still here ?
 
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  • #11
BvU said:
mething under
thanks all, i managed to solve the question above.
 

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