Probability of bulb malfunction

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SUMMARY

The discussion centers on calculating the probability of bulb malfunction using binomial probability. The scenario involves 8 bulbs per pack, with a failure rate of 0.02. The user calculated the probability of no bulbs failing in a pack as 0.8507 using the formula (8C0)(0.02^0)(0.98^8). However, the provided answer of 0.3012 was identified as incorrect, confirming that the user's calculation is accurate and the discrepancy lies with the given answer.

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Homework Statement


consider 8 packs of bulb and let x be the number of bulbs in a pack that 'fail' the first time they are used . If 0.02 of all bulbs of this type fail on their first use and each 8-pack is consider random sample , what is the probability that anyone 8-pack has no bulb fail on the first use ?

Homework Equations

The Attempt at a Solution


I use binomial probability to solve this . But my ans didnt match the ans given
My ans :
(8c0)(0.02^0)(0.98^8) = 0.8507 , the ans given = 0.3012
 
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tzx9633 said:

Homework Statement


consider 8 packs of bulb and let x be the number of bulbs in a pack that 'fail' the first time they are used . If 0.02 of all bulbs of this type fail on their first use and each 8-pack is consider random sample , what is the probability that anyone 8-pack has no bulb fail on the first use ?

Homework Equations

The Attempt at a Solution


I use binomial probability to solve this . But my ans didnt match the ans given
My ans :
(8c0)(0.02^0)(0.98^8) = 0.8507 , the ans given = 0.3012

Your answer is correct; the "given" answer makes no sense at all in this problem.
 
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