Estimating Maximum Error (Multivariable)

Click For Summary
SUMMARY

The discussion focuses on estimating the maximum possible error in the computation of T, defined as T = x(e^y + e^-y), where x = 2 and y = ln(2). The maximum errors for x and y are |dx| = 0.1 and |dy| = 0.02, respectively. The user calculated the maximum error using the formula |E| <= (1/2) * M * (|dx| + |dy|)^2, arriving at an error of 0.036, which contradicts the book's answer of 0.31. The conversation highlights the importance of using linear approximations for error estimation in multivariable functions.

PREREQUISITES
  • Understanding of multivariable calculus, specifically partial derivatives
  • Familiarity with error estimation techniques in calculus
  • Knowledge of linearization and quadratic approximation methods
  • Proficiency in evaluating exponential functions and their derivatives
NEXT STEPS
  • Study the concept of linear approximation in multivariable calculus
  • Learn about the application of Taylor series for error estimation
  • Explore the differences between linear and quadratic approximations
  • Review examples of error analysis in multivariable functions
USEFUL FOR

Students and educators in calculus, particularly those focusing on error estimation in multivariable functions, as well as professionals applying these concepts in engineering and physics.

d-rock
Messages
14
Reaction score
0
Estimating Maximum Error, Odd Question? (Please Help Today!)

Homework Statement


Suppose that T is to be found from the formula T = x(e^y + e^-y), where x and y are found to be 2 and ln(2) with maximum possible errors of |dx| = 0.1 and |dy| = 0.02. Estimate the maximum possible error in the computed value of T.


Homework Equations


|E| <= (1/2) * M * (|x - xo| + |y - yo|) ^ 2


The Attempt at a Solution


dT/dx = (e^y + e^-y) and dT/dy = x(e^y - e^-y)

d2T/dx2 = 0, d2T/dy2 = x(e^y + e^-y) @ (2, Ln(2)) = 2(2 + 1/2) = 5

and lastly d2T/dxy = (e^y - e^-y) @ (2, Ln(2)) = 2 - 1/2 = 1.5


So I believe the M maximum is 5, for the second derivative with respect to y.

Then, I used the equation:

|E| <= (1/2) * 5 * (|dx| + |dy|)^2 = 2.5 * (0.1 + 0.02)^2 = 0.036


So my answer was 0.036. But the book's answer is 0.31. So I am unsure what went wrong or if I overlooked something...?
 
Last edited:
Physics news on Phys.org
I'm not exctaly sure what you doing? Is that a quadratic apporimation to the error

Why not use a linear approximation to the function at the point by finding the gradient of the function there? (which you already have, but then use it to estimate the error...)

dependent on the function, for small dx & dy, generally the linear term will be largest (unless its an extremum) with higher order terms decreasing in magnitude.
 
I don't know what you mean?

The error formula in my book (which is surrounded by Linearization, etc.) has

|E| <= (1/2)*M*(|x-xo| + |y-yo|)^2

where M is the largest possible value of the second derivatives at the point given. Then I just assumed that (x - xo) and (y-yo) are the dx and dy values they gave me, but I'm guessing it's wrong.

So, what linear approximation?
 

Similar threads

Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
3
Views
2K