Estimating Pool Area Using Simpson's Rule

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To estimate the area of a kidney-shaped swimming pool using Simpson's Rule, the widths measured at 2-meter intervals are applied in the formula. The values provided are a = 5.8, b = 6.6, c = 5.4, d = 5.8, e = 5.2, f = 4.8, and g = 5.2. The calculation involves substituting these values into the formula: Area = (4(4a + 2b + 4c + 2d + 4e + 2f + 4g))/6. After performing the calculation, the area should be rounded to the nearest square meter for the final answer. This method is crucial for accurately estimating the pool's area for exam preparation.
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I put this in the homework section a few days ago, but the homework was already due, and I'd like an explanation as to how to do this please. I have a feeling a similar problem will be on the exam.

The widths (in meters) of a kidney-shaped swimming pool were measured at 2 meter intervals as indicated in the figure. Use Simpson's Rule to estimate the area of the pool. Please round the answer to the nearest square meter.

7-7-030alt.gif


a = 5.8
b = 6.6
c = 5.4
d = 5.8
e = 5.2
f = 4.8
g = 5.2



Thanks
 

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I am assuming that a and g were each 2 meters from the edge.
Then Simpson's rule gives 4(4a+2b+4c+2d+4e+2f +4g)/6.
 
Last edited:
There are probably loads of proofs of this online, but I do not want to cheat. Here is my attempt: Convexity says that $$f(\lambda a + (1-\lambda)b) \leq \lambda f(a) + (1-\lambda) f(b)$$ $$f(b + \lambda(a-b)) \leq f(b) + \lambda (f(a) - f(b))$$ We know from the intermediate value theorem that there exists a ##c \in (b,a)## such that $$\frac{f(a) - f(b)}{a-b} = f'(c).$$ Hence $$f(b + \lambda(a-b)) \leq f(b) + \lambda (a - b) f'(c))$$ $$\frac{f(b + \lambda(a-b)) - f(b)}{\lambda(a-b)}...

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