Estimation, bias and mean squared error

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The discussion revolves around estimating the parameter θ from independent random variables X1, X2,..., Xn, each uniformly distributed on [0, θ]. The proposed estimator is m = max(x1,...,xn), and participants are calculating the distribution of M = max(X1, X2,..., Xn). The cumulative distribution function is derived as P(max(X1,...,Xn)≤m) = (m/θ)^n, leading to a density function through differentiation. Clarification is sought on whether to differentiate with respect to θ or m, with guidance provided to use the standard formula for density functions. The conversation emphasizes understanding the correct approach to derive the density from the cumulative distribution function.
stukbv
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Homework Statement



(x1,x2,...xn) is modeled as observed values of independent random variables X1,X2,...Xn each with the distribution 1/θ for x in [0,θ] and 0 otherwise.
A proposed estimate of θ is m = max(x1,...xn) Calculate the distribution of the random variable M=max(X1,X2,...Xn) and considering M as an estimator for θ, its bias and mean squared error.

2. The attempt at a solution
P(max(X1,...Xn)≤m) = P(X1≤m)P(X2≤m)...P(Xn≤m)
via independent of the Xi's.

Then since they have the same distribution this is just
(m/θ)n

So to get the distribution do I just differentiate with respect to θ
Which would give me

n(m/θ)n-1 * (-m/(θ2))

Is this the right way to think about it ?

Thank you
 
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stukbv said:

Homework Statement



(x1,x2,...xn) is modeled as observed values of independent random variables X1,X2,...Xn each with the distribution 1/θ for x in [0,θ] and 0 otherwise.
A proposed estimate of θ is m = max(x1,...xn) Calculate the distribution of the random variable M=max(X1,X2,...Xn) and considering M as an estimator for θ, its bias and mean squared error.

2. The attempt at a solution
P(max(X1,...Xn)≤m) = P(X1≤m)P(X2≤m)...P(Xn≤m)
via independent of the Xi's.

Then since they have the same distribution this is just
(m/θ)n

So to get the distribution do I just differentiate with respect to θ
Which would give me

n(m/θ)n-1 * (-m/(θ2))

Is this the right way to think about it ?

Thank you

You have the (cumulative) distribution function F(m) = Pr{M <= m}. How do you get the density function of M from that? There is a standard formula; you just need to use it.

RGV
 
I know that you differentiate to get the density function but I can't work out whether its with respect to theta (which is what I did above) or with respect to m?
 
##f(m) = {d \over dm} F(m)##.
 
The standard formula would tell you exactly what to do---no confusion!

RGV
 
I see thamk you!
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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