Estimation, bias and mean squared error

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stukbv
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Homework Statement



(x1,x2,...xn) is modeled as observed values of independent random variables X1,X2,...Xn each with the distribution 1/θ for x in [0,θ] and 0 otherwise.
A proposed estimate of θ is m = max(x1,...xn) Calculate the distribution of the random variable M=max(X1,X2,...Xn) and considering M as an estimator for θ, its bias and mean squared error.

2. The attempt at a solution
P(max(X1,...Xn)≤m) = P(X1≤m)P(X2≤m)...P(Xn≤m)
via independent of the Xi's.

Then since they have the same distribution this is just
(m/θ)n

So to get the distribution do I just differentiate with respect to θ
Which would give me

n(m/θ)n-1 * (-m/(θ2))

Is this the right way to think about it ?

Thank you
 
Last edited:
on Phys.org
stukbv said:

Homework Statement



(x1,x2,...xn) is modeled as observed values of independent random variables X1,X2,...Xn each with the distribution 1/θ for x in [0,θ] and 0 otherwise.
A proposed estimate of θ is m = max(x1,...xn) Calculate the distribution of the random variable M=max(X1,X2,...Xn) and considering M as an estimator for θ, its bias and mean squared error.

2. The attempt at a solution
P(max(X1,...Xn)≤m) = P(X1≤m)P(X2≤m)...P(Xn≤m)
via independent of the Xi's.

Then since they have the same distribution this is just
(m/θ)n

So to get the distribution do I just differentiate with respect to θ
Which would give me

n(m/θ)n-1 * (-m/(θ2))

Is this the right way to think about it ?

Thank you

You have the (cumulative) distribution function F(m) = Pr{M <= m}. How do you get the density function of M from that? There is a standard formula; you just need to use it.

RGV
 
I know that you differentiate to get the density function but I can't work out whether its with respect to theta (which is what I did above) or with respect to m?