Calculating the Maximum Safe Volume of Ethanol in a Confined Space

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SUMMARY

The maximum safe volume of ethanol in a confined space can be calculated based on its lower flammability point of 3.5% v/v. For a 100-liter vessel, this translates to a maximum of 3.5 liters of ethanol vapor. To convert this vapor volume back to liquid ethanol, one can use the ideal gas law to determine the number of moles in 3.5 liters of vapor, which is calculated as N = 3.5/22.4. By multiplying the number of moles by the molar mass of ethanol and using its density, the corresponding volume of liquid ethanol can be derived.

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  • Understanding of ethanol's flammability limits
  • Familiarity with the ideal gas law
  • Knowledge of molar mass and density calculations
  • Basic principles of gas behavior under ambient conditions
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  • Learn about the ideal gas law and its applications in real-world scenarios
  • Research the molar mass and density of ethanol for accurate calculations
  • Explore safety regulations regarding flammable substances in confined spaces
  • Study methods for measuring vapor concentrations in laboratory settings
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Chemical engineers, safety officers, laboratory technicians, and anyone involved in handling flammable liquids in confined environments will benefit from this discussion.

Shannon hunt
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Hello
The lower flammability point of ethanol is 3.5% v/v. How can I work out the max volume of ethanol in a specified space to be lower than the flammability point
Eg
If I have a 100l vessel 3.5% will be 3.5l of vapour in that 100l vessel that will make it ignitable - how can I convert 3.5 l of ethanol vapour back to the volume of ethanol as liquid(pressure and t at ambient at this point)
Thank u
 
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You can have an estimate by assuming the vapors behave like an ideal gas.
In normal conditions, you can find the number of moles in 3.5 L of vapors like
N=3.5/22.4
Then multiply by molar mass o get the mass of ethanol in these 3.5 L.
And knowing the mass and density of liquid you can find the volume of liquid.
 

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