Euclidean signature and compact gauge group

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
5 replies · 2K views
Einj
Messages
464
Reaction score
59
Hello everyone,
I have been reading around that when performing the analytic continuation to Euclidean space ([itex]t\to-i\tau[/itex]) one also has to continue the gauge field ([itex]A_t\to iA_4[/itex]) in order to keep the gauge group compact.
I already knew that the gauge field had to be continued as well but I didn't know anything about keeping the gauge group compact. Can someone explain it to me?

Thanks!
 
Physics news on Phys.org
Do you have any idea on how to show it or any source I could look at? Thanks for you reply!
 
I would guess any decent grad text on field theory might cover this. I don't know of one myself. I recall reading something on the complexification in Ryder's book "Quantum Field Theory" but I don't recall him speaking of justification. I don't recall Kaku addressing it directly in his book but I haven't peeked in his text in a while and didn't read it extensively when I last did. Maybe someone else has a suggestion?
 
The point is that you entirely go from Minkowski space with a fundamental form of signature (1,3) (or (3,1) if you come from the east coast ;-)) to Euclidean space, i.e., the proper orthochronous Lorentz group is substituted by O(4). So all four-vectors become Euclidean vectors. The gauge group stays as it is, i.e., a compact Lie group.
 
  • Like
Likes   Reactions: Einj
Oh I see! Thanks a lot