Euclid's formula/Perfect Numbers #2

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SUMMARY

The discussion centers on proving that the sum of the reciprocals of all divisors of a perfect number equals 2, utilizing Euclid's formula for perfect numbers. The approach involves listing the divisors of a perfect number \( n \) and recognizing that the sum of these divisors is \( 2n \). By pairing each divisor \( d_i \) with its corresponding divisor \( d_{k-i+1} \), the relationship \( \frac{1}{d_i} + \frac{1}{d_{k-i+1}} = \frac{2}{n} \) is established, leading to the conclusion that the total sum of the reciprocals is indeed 2.

PREREQUISITES
  • Understanding of Euclid's formula for perfect numbers
  • Familiarity with divisor functions in number theory
  • Basic knowledge of algebraic manipulation and equations
  • Concept of reciprocals and their properties
NEXT STEPS
  • Study the properties of perfect numbers and their relationship to Mersenne primes
  • Explore the divisor function and its applications in number theory
  • Learn about the implications of Euclid's formula in modern mathematics
  • Investigate the historical context and significance of perfect numbers
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Mathematicians, students studying number theory, educators teaching advanced mathematics, and anyone interested in the properties of perfect numbers and their divisors.

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Homework Statement



Prove that the sum of the reciprocals of all divisors of a perfect number is equal to 2.

Homework Equations



Euclid's formula for perfect #'s

The Attempt at a Solution



I am so lost.
 
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Let d1, d2,..., dk be a (ordered) list of divisors of perfect number n where d1 = 1, dk = n. It is clear that the sum of all these divisors is 2n.

Observe that d1dk = n implies d1 = n/dk, which in turn implies that 1/d1 = dk/n.

Do this same thing for d2dk-1 = n implies... etc
Now you have each reciprocal written as d/n where d is a divisor of n, so add them up.
 

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