Find the domain of f(x,y)=sqrt(5xy-2y^2)
The Attempt at a Solution
As far as I understand it's all about solving inequalities when you have this kind of problem.
The problem doesn't state it is in ℝ2 but I'm pretty sure it is.
So no negative numbers under the root.
Therefore 5xy ≥ -2y^2
x ≥ -2y/5 or -y ≥ 5x/2
But how exactly is this useful information?
So I looked up the topic on Youtube, Multivariable Calculus: Finding and Sketching the Domain.
It sounds perfect and the guy has two examples and one even has a root in it.
Sadly I still don't get it :/