Evaluate: ∇(∇r(hat)/r) where r is a position vector

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Homework Help Overview

The discussion revolves around evaluating the expression ∇(∇r(hat)/r), where r is defined as a position vector. Participants are exploring vector calculus concepts without relying on specific coordinate systems.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants have attempted to apply vector identities and have discussed the implications of the divergence and curl of the position vector. There are questions about the use of vector analysis identities and how they can aid in simplifying the expression.

Discussion Status

Some participants are providing guidance on potential approaches, such as using vector analysis identities to break down the problem further. There is an ongoing exploration of the relationships between the equations presented, but no consensus has been reached on the next steps.

Contextual Notes

There is mention of constraints regarding the use of coordinate systems and the need for more details in the problem statement. Participants are also considering the implications of the provided equations on their attempts.

Dave-o
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Homework Statement


∇ . r = 3, ∇ x r = 0

Homework Equations

The Attempt at a Solution


So far I've gotten up to ∇(∇^2 r)
 
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Hi Dave-o and welcome to PF. :welcome:You need to provide more details about what the problem is, the relevant equations and your attempt at a soluton before we can help you.
 

Homework Statement



Not using any Cartesian or any other coordinates but rather the facts that (see equations, r^ is the position vector)..
Evaluate:
∇( ∇ . (r^ / r))

Homework Equations



∇ . r^ = 3, ∇ x r^ = 0, ∇r = r^ / r

The Attempt at a Solution


From the 3rd equation I got ∇( ∇ . ∇r) => ∇(∇^2 r)

I don't know where to go from there
 
Are you allowed to use vector analysis identities? What comes to mind is ## \vec{\nabla} \cdot (\phi \vec{A})=\phi \vec{\nabla} \cdot \vec{A}+\vec{A} \cdot \vec{\nabla}\phi##. You can use this to find the term in parentheses and then take its gradient. You should also be allowed to use the expression for the gradient of 1/r.
 

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