- #1
grantdenbrock
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Homework Statement
I need to show that $$\del*\vec{A(\vec{r})}=\frac{\mu}{4\pi}\int{\frac{\vec{J{vec\r'}}}{\vec{R}}}d\tau=0$$
where A is the vector potential and R refers to "script r" or (r-r') where r is source point of charge and r' is the measurement point. tau refers to a volume integral. I have tried many times now to show this by bringing del into the integrand using product rules and the fact that $$\delR=-\del'R'$$ but cannot make it equal zero. I am not sure if there is something I have overlooked or another method to use but any help or suggestions are much appreciated!
Homework Equations
del*R=-del'R' must be used at some point[/B]
The Attempt at a Solution
My solution thus far goes like this (Sorry My latex is awful so I will just write out my method)
1) bring Del into the integrand
2) using product rule rule of dot products expand into 2 terms each with its own dot product
3) del*J' =0 since del operates on unprimed coordinates
4) J' del*1/R does not equal zero therefore integrand does not equal zero :/[/B]