Evaluating a Riemann Sum for $\int^{-2}_{5} t^2 + 6t - 4 dt$

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SUMMARY

The integral $\int^{-2}_{5} (t^2 + 6t - 4) dt$ can be evaluated using the limit of a Riemann sum, specifically by applying sigma notation properties. The limit is expressed as $\lim \sum ( ( \frac{7i}{n})^2 + 6 \frac{7i}{n} - 4 ) \Delta t$, where $\Delta t = \frac{7}{n}$. The final result of the Riemann sum evaluation yields approximately 233.3, contrasting with the direct integral evaluation result of -54.66. Key errors identified include the incorrect integration limits and neglecting the negative sign in the integrand.

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[SOLVED] Riemann sum

Evaluate \int^{-2}_{5} t^2 + 6t - 4 dt by writing it as the limit of a Riemann sum, and taking the limit of that sum using properties of sigma notation. (Do NOT use the fundamental theorem of calculus to evaluate this integral.)

Important stuff:

\sum i^2 = \frac{n(n+1)(2n+1)}{6}

\sum i = \frac{n(n+1)}{2}

And the solution: (Where I write "lim" I mean limit as n-->infinity. Where I write the summation sign I mean from i=1 to n.)

lim \sum t^2 + 6t - 4 \Delta t

\Delta t = \frac{5 - (-2)}{n}

t = i \Delta t = \frac{7i}{n}

etc, etc.

= \frac{343}{3} + 147 + 28

Which is about 233.3...

When I did the same thing by just doing the integral, I got -54.66...
 
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The difficulty is that you haven't shown HOW you got either of those values. Your \Delta x should be - since you are integrating from 5 down to -2. You have also neglected the "-" on "- 4" in the integrand.
 
HallsofIvy said:
The difficulty is that you haven't shown HOW you got either of those values. Your \Delta x should be - since you are integrating from 5 down to -2. You have also neglected the "-" on "- 4" in the integrand.

Sorry, I messed up the thing I meant for it to be from -2 to 5 but I put the numbers in the wrong places when I was typing it up :P

Ok :) This is the "etc, etc." Where did I miss a "-" on the -4 ?

lim \sum t^2 + 6t - 4 \Delta t

lim \sum ( ( \frac{7i}{n})^2 + 6 \frac{7i}{n} - 4 ) \frac{7}{n}

lim \sum ( \frac{7i}{n})^2 * \frac{7}{n} + 6 \frac{7i}{n} * \frac{7}{n} - 4 * \frac{7}{n}

lim \sum \frac{7^2}{n^2} * i^2 * \frac{7}{n} + 6 \frac{7}{n} * i * \frac{7}{n} - 4 * \frac{7}{n}

lim \frac{7^2}{n^2} * \frac{n(n+1)(2n+1)}{6} * \frac{7}{n} + 6 \frac{7}{n} * \frac{n(n+1)}{2} * \frac{7}{n} - 4n * \frac{7}{n}

lim \frac{7^3}{6} * \frac{2n^2 + 3n + 1}{n^2} + 21 * 7 * \frac{n+1}{n} - 4 * 7

\frac{7^3}{3} + 21 * 7 - 4 * 7

If you can follow the algebra there :)

------

Sorry all for not realizing this part of the forum wasn't for homework. If anyone has the ability to move it to the right part of the forum, it would be shiny.
 
Last edited:

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