Evaluating Integral F dot dA using Divergence Theorem

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SUMMARY

The discussion focuses on using the Divergence Theorem to evaluate the integral of the vector field F = (2x-z)i + x²yj + xz²k over the surface enclosing the unit cube. The correct divergence of F is calculated as div F = x² + 2xz + 2. The evaluation of the integral over the defined limits of the unit cube, specifically from 0 to 1 for x, y, and z, leads to the final result of 28/3 for the integral. The initial assumption of the region from -1 to 1 was incorrect, as the unit cube is defined within the bounds of 0 to 1.

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Homework Statement



use the divergence theorem to evaluate the integral F dot dA

F = (2x-z)i + x2yj + xz2k

s is the surface enclosing the unit cube and oriented outward

Homework Equations





The Attempt at a Solution



is the the region from -1 to 1 for x y and z

div F = x2 + 2xz + 2

x2 + 2xz + 2 dx = x3/3 + x2z + 2x from -1 to 1

14/3 dy = 14y/3 from -1 to 1 = 28/3

28/3 dz = 28z/3 from -1 to 1 = 56/3

is this correct
 
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No, the "unit cube" is defined by 0\le x\le 1, 0\le y\le 1, 0\le z\le 1.
 

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