Evaluating Integrals on Ellipse: C and C

  • Thread starter Thread starter teleport
  • Start date Start date
  • Tags Tags
    Ellipse Integrals
Click For Summary

Homework Help Overview

The discussion revolves around evaluating integrals on ellipses, specifically focusing on the integral of a given expression over the first ellipse and using that result to evaluate a similar integral over a second ellipse. The subject area includes calculus and vector calculus, particularly the application of Green's Theorem.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the evaluation of the integral for the first ellipse and explore methods for the second integral. There are questions about the use of Green's Theorem and the implications of the integrand being undefined at a specific point. Some participants express uncertainty about the methods available to them.

Discussion Status

The discussion is ongoing, with some participants providing their results and others questioning the validity of those results. There is an acknowledgment of different approaches to the problem, and while some guidance has been offered regarding the integrand's behavior, no consensus has been reached on the methods to apply for the second integral.

Contextual Notes

Participants note that the integrand is undefined at the origin, which is located within both ellipses. This raises questions about the implications for the evaluation of the integrals and the methods that can be used.

teleport
Messages
240
Reaction score
0

Homework Statement


(i) Evaluate

\int_C \dfrac{-ydx + xdy}{9x^2 + 16y^2}

when C is the ellipse

\dfrac{x^2}{16} + \dfrac{y^2}{9} = 1

(ii) Use the ans to (i) to evaluate the integral along C' = ellipse:

\dfrac{x^2}{25} + \dfrac{y^2}{16} = 1


Homework Equations





The Attempt at a Solution



I have done (i) but have no clue about (ii). great thnx for any help.
 
Physics news on Phys.org
Okay, what did you get for (i)? I can think of a number of ways that might help you answer (ii) but since you have shown no work at all I don't know which way would be appropriate for you. Do you know Green's Theorem?
 
got pi/6 for i. didn't use green's for that. the other way is easier. for ii u can't use green's since it would either be too complicated or impossible to integrate. yes i know green's thm. sorry for not showing any work. i just don't know what to do for ii.
 
That's not at all what I get for (i). And the problem with (ii) is I don't know what theorems or methods you have available. I do notice that the integrand is defined everywhere except at (0,0) which is inside both ellipses.
 
checked it and still got the same. is it allowed to say 9x^2 + 16y^2 = 144 on that integral? that's something I'm using.

for ii, if u could mention some of the methods u have in mind, i might recognize it as something given in class. thnx
 
My apologies. I just screwed up (1) by copying part of the problem incorrectly. Yes, \pi/6 is the correct answer.

My point about the integrand not being defined at (0,0) was that you make a cut from the outer ellipse to the inner, integrate around one ellipse, then up that cut to the other and back. Then you are integrating around a curve that does NOT have (0,0) in its interior. The integral around that path will be 0, showing that the integral around the two ellipses is the same.
 
and why is it 0? what does the integrand not being defined at (0,0) has to do with that? by a cut do u mean to make a line connecting the 2 ellipses? could u explain more please?
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
2
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K