Evaluating Limits Homework: t^2+1

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SUMMARY

The limit evaluation discussed is for the expression \(\lim_{t\rightarrow3} \frac{(t+1)^2}{(t^2+1)}\). The original confusion stemmed from the inability to factor the denominator \(t^2 + 1\) as one could with \(t^2 - 1\). However, the solution can be directly evaluated by substituting \(t = 3\) into the expression, leading to a definitive answer without the need for factorization.

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Homework Statement



[itex]\lim_{x\rightarrow3} \stackrel{(t+1)^2}{(t^2+1)}[/itex]

Homework Equations





The Attempt at a Solution



if the bottom was t^2 - 1 i could factorise and cancel but when its t^2+1 I am not sure how to go...
 
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gtfitzpatrick said:

Homework Statement



[itex]\lim_{x\rightarrow3} \stackrel{(t+1)^2}{(t^2+1)}[/itex]

Homework Equations





The Attempt at a Solution



if the bottom was t^2 - 1 i could factorise and cancel but when its t^2+1 I am not sure how to go...
Here's you limit.

Note: for fractions, use \frac{}{}, not \stackrel{}{}

[tex]\lim_{x \to 3} \frac{(t+1)^2}{(t^2+1)}[/tex]

You can evaluate this limit directly.
 
oh gosh, i didnt even check that.
that should have been i first move.
thanks mark
 

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