Every subgroup of index 2 is normal?

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Every subgroup H of a group G with index 2 is normal, as it can be shown that for any element g in G, the left coset gH and the right coset Hg must be equal. Since there are only two distinct cosets, H and its complement, any element from the complement will also yield the same coset structure. This leads to the conclusion that gN = Ng for all g in G, confirming that H is indeed a normal subgroup. The discussion highlights the importance of understanding coset partitioning in proving subgroup normality. Overall, the proof relies on the properties of cosets in groups of index 2.
Oster
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I have to prove that every subgroup H of a group G with index(number of distinct cosets of the subgroup) 2 is normal.

I don't know how to start :'(

Please help.
 
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Hi Oster! :smile:

You must prove that gN=Ng for all g. But what exactly are the cosets of N??
 
If the element g comes from H then both gH and Hg are equal to H.
If g comes from H complement then i know it must represent the "other" coset. Since cosets partition G, i know both these cosets must be equal to H complement.
More or less correct?
 
Yes, that's good!
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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