Exercises for Feyman Lectures on Physics

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Homework Statement
1.10 the intensity of a collimated,parrallel beam of potassium atoms is reduced 3.0% bya layer of argon gas 1.0mm thick at a pressure of 6.0x10e4(e=exponent)mmHg.
Calculate the effective target area A per argon atom
Whats a effective target area?
Relevant Equations
no equations
Whats a effective target area?
 
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another question, the 1mm layer is the depth or the diameter I am really confuse in that
 
I think is important because if the layer of argon doesn't exist the intensity the beam throws the particles will be greater
 
and if the layer is thicker the velocity of the particle will be less than in the original problem
 
The assumption here is that any particle in the beam that is scattered is lost from the beam. The ones that get through do not hit anything.
Are there more questions that follow this set up (I am assuming yes}?
 
so,with the layer of argon, 3% of the particle don't get through the beam.Im correct?
(Sorry from the bad grammar I am good at it)
 
number =argon ifthis is corect i see why number of molecules/by the volume
because do that you find the volume of 1 molecule of argon atom
Im correct?
 
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Here's a similar problem. I have a window 1mx1m. I festoon it with 100 round black dots and notice that the total light streaming through diminishes by 5%. How big (area) is a black dot?
 
the total dots should cover 5%of the window so if 100% =100m2 that means that the total area of the dots are 5m2 and is one dot = 0.05m2?
 
i finish the problem,THANK YOU SOOOO MUCH
 
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