Expanding Wavefunction in Infinite Well: Fourier Analysis

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To find the wavefunction of a particle in an infinite well after its expansion from [-a, a] to [-b, b], Fourier analysis is applied. The initial wavefunction is given as ψ(x) = u_1^+(x;a) = cos(πx/2a)/√a for |x| < a. The coefficients a^{+}_n for the even wavefunctions in the expanded box are calculated using the integral a^{+}_n = (1/b) ∫_{-b}^{b} (cos(πx/2a)/√a) * (cos(πx/2b)/√b) dx. After determining these coefficients, the time dependence is incorporated to complete the wavefunction. This approach effectively describes the particle's behavior in the new well dimensions.
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I have an infinite well from -a to with a particle in its ground. The initial wavefunction is then

\psi(x) = u_1^+(x;a) = cos(\pi x/ 2a)/\sqrt{a} for |x| < a.

In order to get the wavefunction for this particle when box that is instantaneously expanded to [-b,b] should I apply Fourier analysis via

a^{+}_n = 1/b \int_{-b}^{b}cos(\pi x/ 2a)/\sqrt{a}\cdot cos(\pi x/ 2b)/\sqrt{b}dx

where a^{+}_n is the coefficient of the even wavefunction with that n in the expanded box?
 
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Yes, then put in the time dependence.
 

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