Expansion of Solids: Brass and Lead Rods at Different Temperatures

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Homework Help Overview

The discussion revolves around the thermal expansion of a brass rod and a lead rod, both initially 80 cm long at 0 degrees Celsius, when subjected to a temperature increase to 100 degrees Celsius. Participants are exploring how to calculate the separation of the free ends of the rods based on their coefficients of linear expansion.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are discussing the basic equation for thermal expansion and questioning how to apply it to the given problem. There is an emphasis on showing work and identifying where difficulties arise.

Discussion Status

Some participants are prompting others to demonstrate their understanding and efforts before seeking answers. A specific formula for thermal expansion has been mentioned, indicating a potential direction for the discussion.

Contextual Notes

Participants are encouraged to clarify their reasoning and assumptions regarding the coefficients of linear expansion provided for both materials. There is a focus on ensuring that the calculations align with the physical properties of the materials involved.

sudhamshu
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Q 1. A brass rod and a lead rod each 80 cm long at 0 degree celsius are clamped together at one end with their free end coinciding. The separation of the free ends of the rod if the system is placed in a steam bath at 100 degree celsius is ( coefficient of linear expansion of lead = 28*10^-6/degree celsius, coefficient of linear expansion of brass
= 18 * 10^-6/degree celsius) :
a. 0.2 mm
b. 0.8 mm
c. 1.4 mm
d 1.6 mm

Kindly Answer the above with the explanation
Sudhamshu
 
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Kindly show an effort, first. :smile:
 
Show us your work and where you got stuck. What's the basic equation describing thermal expansion?
 
is this the answer?

:smile:
0.8 because the formula is delta L=(alpha) (L initial)(delta Temp.)
 
Last edited:

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