What is the Temperature at which the Gap Between Two Bars will be Closed?

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Homework Help Overview

The problem involves determining the temperature at which the gap between a brass bar and an aluminum bar, each fixed to immovable walls, will close. The initial gap is specified as 1.3 x 10-3 m at 28°C, with given coefficients of linear expansion for both materials.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between the linear expansions of the two bars and the gap closure. There is uncertainty about how to set up the equations due to the different lengths and expansion coefficients of the bars.

Discussion Status

Some participants have proposed equations relating the expansions of the two bars to the gap, with one suggesting a specific approach to find the temperature at which the bars will touch. However, there is no explicit consensus on the correctness of the arithmetic or the method used.

Contextual Notes

Participants are navigating the complexities of the problem, including the implications of the different lengths and expansion rates of the materials involved. There is a focus on ensuring the correct application of the linear expansion formula without reaching a definitive conclusion.

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Homework Statement



A brass bar and an aluminium bar are each attached opposite each other to immovable walls. (There is a diagram, but I think the idea is clear enough). There is a gap between the two bars of 1.3x10-3m at 28°C.

At what temperature will the gap be closed?

coefficient of linear expansion of brass = 19x10-6 (C°)-1
aluminium = 23x10-6 (C°)-1

Length of brass bar = 2.0m
Length of aluminium bar = 1.0m

Homework Equations



ΔL = \alphaLoΔT

The Attempt at a Solution



I'm not sure where to begin really. Obviously part of the problem is that the two rods are not going to meet in the middle as they expand.

I have 2 unknowns for both rods in the equation for linear expansion, so it's not really helpful to rearrange for ΔT and set them equal to each other.

If you could get me started that would be great,

thanks!
 
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What must the sum of the ΔL's equal?
 
1.3 x 10^-3 m

Can I say:

ΔL + ΔL = \alphaLoΔT + \alphaLoΔT

1.3x10^-3 = (3.8x10^-5 + 23x10^-6)ΔT

ΔT = 21.3 degrees C

28 + 21.3 = Temp when bars will touch
 
Last edited:
BOAS said:
1.3 x 10^-3 m

Can I say:

ΔL + ΔL = \alphaLoΔT + \alphaLoΔT

1.3x10^-3 = (3.8x10^-5 + 23x10^-6)ΔT

ΔT = 21.3 degrees C

28 + 21.3 = Temp when bars will touch
I didn't check your arithmetic, but that is definitely the way to solve it.
 
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I'll check and double check.

Thanks a lot!
 

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