Expectation value for electron in groundstate

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Homework Help Overview

The discussion revolves around calculating the expectation value for the radial distance \( r \) of an electron in the ground state of a one-electron atom, specifically focusing on the expression \( \langle r \rangle = \frac{3}{2} \frac{a_{0}}{Z} \). Participants are exploring the mathematical setup and integration involved in this quantum mechanics problem.

Discussion Character

  • Mathematical reasoning, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the correct normalization constant \( C_{100} \) and its derivation. There are attempts to set up the integral for the expectation value, with some participants expressing confusion over limits and the integration process. Questions arise regarding the proper use of spherical coordinates and the volume element in the integral.

Discussion Status

The discussion has progressed with participants identifying mistakes in their initial setups. Some have found clarity in using spherical coordinates, while others continue to question their calculations and the correctness of the normalization constant. There is no explicit consensus on the final answer, but productive guidance has been shared regarding the integration process.

Contextual Notes

Participants note the importance of verifying constants from textbooks and the need to correctly set limits for integrals in spherical coordinates. There is an acknowledgment of potential errors in the initial assumptions or calculations that may affect the outcome.

Cp.L
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Homework Statement


Show that the expectation value for r for an electron in the groundstate of a one-electron-atom is:
<r>=(3/2)a[itex]_{0}[/itex]/Z



Homework Equations


Expectationvalue:
<f(x)>=∫[itex]\psi[/itex]*f(x)[itex]\psi[/itex]dx, -∞<x>∞

[itex]\psi[/itex][itex]_{100}[/itex]=C[itex]_{100}[/itex] exp(-Zr/a[itex]_{0}[/itex]), [itex]a_{o}\ =\ 0.5291\ \times\ 10^{-10}m , h\ =\ 6.626\ \times\ 10^{-34}\ J\ s[/itex]


The Attempt at a Solution


Im stuck..
 
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Cp.L said:

Homework Statement


Show that the expectation value for r for an electron in the groundstate of a one-electron-atom is:
<r>=(3/2)a[itex]_{0}[/itex]/Z



Homework Equations


Expectationvalue:
<f(x)>=∫[itex]\psi[/itex]*f(x)[itex]\psi[/itex]dx, -∞<x>∞

[itex]\psi[/itex][itex]_{100}[/itex]=C[itex]_{100}[/itex] exp(-Zr/a[itex]_{0}[/itex]), [itex]a_{o}\ =\ 0.5291\ \times\ 10^{-10}m , h\ =\ 6.626\ \times\ 10^{-34}\ J\ s[/itex]


The Attempt at a Solution


Im stuck..

What is stopping you from doing the integral? Of course, first you must determine the correct value of C100; do you know how to do that?

RGV
 
Hi, yes i used that C[itex]_{100}[/itex] =(1/[itex]\sqrt{\pi}) (\frac{z}{a_{0}}[/itex])[itex]^{3/2}[/itex]

Then i do the integral, but i must be doing it wrong cause i end up with e[itex]^{\frac{-2zr}{a_{0}}}[/itex] in the answer and also a problem of e[itex]^{∞}[/itex]
 
Show your work.
 
Ok, i found a mistake, but still don't get it right.
I write:

<r>=[itex]\frac{1}{\pi}[/itex][itex]\frac{z_{0}^{3}}{a_{0}^{3}}[/itex]∫e[itex]^{\frac{-2Zr}{a_{0}}}[/itex]r dr

Where the limits are from -∞ to ∞

Integrating i let U= r, du=1, dv= e[itex]^{\frac{-2Zr}{a_{0}}}[/itex], V=[itex]\frac{a_{0}}{-2Z}[/itex]e[itex]^{\frac{-2Zr}{a_{0}}}[/itex]

this integration leaves me with e[itex]^{∞}[/itex], or is there some trick for e[itex]^{-∞}[/itex] - e[itex]^{∞}[/itex]
 
The integral should be from 0 to infinity. You also have a mistake somewhere else as your expression has units of 1/length.
 
Last edited:
Oh yes that's logical since its the radius, thanks. Yes and the integration by parts should be
u=r
du=dr
dv=e[itex]^{\frac{-2Zr}{a_{0}}}[/itex]
v=[itex]_{}\frac{a_{0}}{-2Z}[/itex]e[itex]^{\frac{-2Zr}{a_{0}}}[/itex] dr

integrating [itex]\frac{z^{3}}{\pi a_{0}}[/itex]∫e[itex]^{\frac{-2Zr}{a_{0}}}[/itex] r dr from 0 to ∞ with these vaues i get
<r>= -[itex]\frac{Za_{0}}{4\pi}[/itex]

I wonder if my C[itex]_{100}[/itex] might be wrong..
 
How did you find C100?
 
It was listed in my book, for the groundstate of an hydrogen atom so it should actually be correct.
 
  • #10
You need to go back and review spherical coordinates so you can set up the integrals correctly. In particular, you need to fix your limits and get the volume element right.
 
  • #11
Cp.L said:
It was listed in my book, for the groundstate of an hydrogen atom so it should actually be correct.

You should verify for yourself the value given in the book. If you cannot get the book's value, that is a signal that you may be doing something wrong---or possibly that the book made an error---but you should go with the first hypothesis unless you have overwhelming evidence to the contrary.

Once you are able to get the correct value of C100 you will be in a better position to find <r>.

RGV
 
  • #12
Hi, thanks a lot. It really helped to use spherical coordinates :) got the correct answer now :)
 

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