Expectation value of the square of the observable

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SUMMARY

The discussion focuses on calculating the expectation value of the square of an observable in quantum mechanics. The correct formula for the expectation value of an observable's square is established as \(\langle Q^2 \rangle = \int_{-\infty}^{\infty} \Psi^* (\hat{Q} \Psi)^2 \; dx\), emphasizing the necessity of double application of the operator. User dextercioby provided clarification that the square is defined by the operator's double application, leading to more elegant solutions. This highlights the importance of understanding operator application in quantum mechanics.

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Homework Statement


I know how to compute the expectation value of an observable. But how does one compute the expectation value of an observable's square?

Homework Equations


[tex]\langle Q \rangle = \int_{-\infty}^{\infty} \Psi^* \hat{Q} \Psi \; dx[/tex]
[tex]\langle Q^2 \rangle = \int_{-\infty}^{\infty} \Psi^* (\hat{Q} \Psi)^2 \; dx \; ?[/tex]
 
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No, the square is defined by double application of the operator

[tex]A^2 \psi =A\left(A \psi \right) \ , \forall \psi\in D(A) \ \mbox{and} \ {} A\psi \in D(A)[/tex]
 
I tried double application after I posted and got more elegant answers. Thanks dextercioby.
 

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