- #1
robert80
- 66
- 0
You all know that the Fermats last theorem is solved for some years and that the equation
a^n + b^n = c^n
is solved when a,b,c being the natural numbers only for n = 2.
I would like to expand a problem:
Can anybody proove that:
a^n + b^n + c^n = d^n has a solutions a,b,c,d in the natural numbers for n = 3 and that for each higher n equation is non solveable?
Lets carry on: Can anybody proove that a^n + b^n + c^n + d^n + e^n = f^n for n = 4 the last solution exists?and for n>4 there are no solutions?
Thanks,
Robert
it would be very nice to find the rule, how many particles on the power of n you have to sum that you get the last solution of the equation in order of given n.
a^n + b^n = c^n
is solved when a,b,c being the natural numbers only for n = 2.
I would like to expand a problem:
Can anybody proove that:
a^n + b^n + c^n = d^n has a solutions a,b,c,d in the natural numbers for n = 3 and that for each higher n equation is non solveable?
Lets carry on: Can anybody proove that a^n + b^n + c^n + d^n + e^n = f^n for n = 4 the last solution exists?and for n>4 there are no solutions?
Thanks,
Robert
it would be very nice to find the rule, how many particles on the power of n you have to sum that you get the last solution of the equation in order of given n.