Experiment and pu tiron nail into water

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SUMMARY

The discussion centers on the corrosion of iron nails when submerged in water, leading to rust formation. The chemical process involves iron (Fe) losing electrons, which react with oxygen and water to form hydroxides, ultimately resulting in red rust (Fe2O3) from green rust (Fe(OH)2). The participants explore the weight gain of the nail during rusting and electrolysis, questioning the effects of impurities and the nature of the electrolyte solution, specifically hydrochloric acid (HCl). Key insights include the role of oxidation and reduction in mass changes during these processes.

PREREQUISITES
  • Understanding of electrochemistry, specifically oxidation and reduction reactions.
  • Familiarity with the chemical processes of rust formation, including Fe(OH)2 and Fe2O3.
  • Knowledge of electrolytic processes and the role of cathodes and anodes.
  • Basic chemistry of solutions, particularly the effects of impurities in water.
NEXT STEPS
  • Research the electrochemical properties of iron and its alloys, focusing on corrosion mechanisms.
  • Study the effects of pH on rust formation and the stability of iron hydroxides.
  • Learn about the electrolysis of hydrochloric acid and its impact on iron electrodes.
  • Investigate the formation of complex oxides and spinels during corrosion processes.
USEFUL FOR

Chemistry students, materials scientists, and anyone involved in corrosion prevention and electrochemical research will benefit from this discussion.

Mathysics
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So i did an experiment and pu tiron nail into water and serveral days later it starts to rust.

and i looked at the book and the chemical process is
1)Fe loses electron
2) that electron + oxygen + water produces hydroxide
3) hydroxide and Fe ion reacts and form Fe(OH)2, green rust
4) green rust + oxygen become red rust + water

but i don't know why it is red rust that is formed on the nail. If the pH level is low will it becomes red rust or stays at green rust?

THX!
 
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Crystal structure of green rust formed by corrosion of cast iron
http://www.nature.com/nature/journal/v259/n5540/abs/259200a0.html

http://en.wikipedia.org/wiki/Iron(II)_hydroxide
If the solution was not deoxygenated and the iron reduced, the precipitate can vary in color starting from green to reddish brown depending on the iron(III) content.
Look at the possible reactions of Fe and aqueous solutions, and also at the forms of Fe oxides, hydroxides and oxyhydroxides.

Are there any cation impurities or alloying elements?
 


well the h2o will have impurities, and the nail is actually steel and iron?

As part of the experiment i am also to de rust the nail.

would the nail suppose the gain weigh after electrolysis? Because when the nail rust it gains weigh, and if de rust will it lose weigh? but my nail gains weigh after electrolysis and I have no idea why is that...
 


Mathysics said:
well the h2o will have impurities, and the nail is actually steel and iron?

As part of the experiment i am also to de rust the nail.

would the nail suppose the gain weigh after electrolysis? Because when the nail rust it gains weigh, and if de rust will it lose weigh? but my nail gains weigh after electrolysis and I have no idea why is that...
The nail is probably steel, i.e. an alloy of iron. It would gain mass from the oxidation of the steel components, i.e., pickup oxygen in the form of oxides, or hydroxides.
 


Astronuc said:
The nail is probably steel, i.e. an alloy of iron. It would gain mass from the oxidation of the steel components, i.e., pickup oxygen in the form of oxides, or hydroxides.
well yes when the nail form rust it is heavier but I am not sure about the cathode (rusted iron) will gain or lose weight. I re-tested again at school day and still got the same result. So my question is how come the nail rust it gains weight, and when the nail being de-rusted it gains weight again?

Oh.. also the anode iron (sacrifical iron) forms green stuff aorund it, I am not sure what that is too!
 
Last edited:


How much mass is gained?

In addition to forming oxides with iron and other steel components, there may be spinels or other complex oxides. Is the electrolyte solution aerated or de-aerated water?

Note: reduction occurs at the cathode. So mass deposition would occur at that cathode.

http://bouman.chem.georgetown.edu/S02/lect25/lect25.htm
bouman.chem.georgetown.edu/S02/lect25/e3a.jpg

Also note the different reactions with water. Even in electrolysis, if one liberates hydrogen, the oxygen is available to react with the cathode.

What reactions are taking place in the cell, particularly at the cathode?
 


Astronuc said:
How much mass is gained?

In addition to forming oxides with iron and other steel components, there may be spinels or other complex oxides. Is the electrolyte solution aerated or de-aerated water?

Note: reduction occurs at the cathode. So mass deposition would occur at that cathode.

http://bouman.chem.georgetown.edu/S02/lect25/lect25.htm
bouman.chem.georgetown.edu/S02/lect25/e3a.jpg

Also note the different reactions with water. Even in electrolysis, if one liberates hydrogen, the oxygen is available to react with the cathode.

What reactions are taking place in the cell, particularly at the cathode?

the cathode nail takes 25mins to gain 2.36 -> 2.4. This is not too accurate because there are those (green stuff?) form around the nail and when i pull the nail out and measure the weight those green stuff fall out and stay in solution.

solution is HCl

the rust on cathode nail should be forming FeCl2 then will form iron as the cathode nail becomes negative? Is hydrogen gas also produced at cathode?
 


By 2.36 -> 2.4, is this a mass changing from 2.36 g to 2.4 g? I presume units are grams.

Does one measure the nail both times in the same condition, i.e. dry?
 


Astronuc said:
By 2.36 -> 2.4, is this a mass changing from 2.36 g to 2.4 g? I presume units are grams.

Does one measure the nail both times in the same condition, i.e. dry?

sorry my computer was having some problems...

yes it changes from 2.36 to 2.6 in grams and are both measured in the same condition
 

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