Explaining a Physics Formula in Non-Physics Terms: Answer B

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The discussion centers on understanding the physics formula "sinΘR = 1.22 λ/d," specifically regarding its application and the concept of resolving power. Participants seek clarification on how the dish's diameter influences resolving power and the meanings of the symbols in the formula. There is a suggestion that asking for explanations in simpler terms may not be effective in a physics-focused forum. Ultimately, the original poster indicates they have resolved their questions. The conversation highlights the importance of engaging with the material and seeking deeper understanding in technical discussions.
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Homework Statement
If the diameter of a radar dish is doubled, what happens to its resolving power assuming that all other factors remain unchanged?

A) The resolving power quadruples.
B) The resolving power doubles.
C) The resolving power is reduced to 1/2 of its original value.
D) The resolving power is reduced to 1/4 of its original value.
E) The resolving power does not change unless the focal length changes.

The answer is B.
Relevant Equations
sinΘR = 1.22 λ/d
According to the equation, the answer is B.
Since the lecture didn't cover much about it, can someone explain this formula in a less physics way? Thanks.
 
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What have you done so far? E.g what have you found out ?
What is meant by resolving power?
Why will the dish’s diameter affect the resolving power?
What do the symbols in the formula “sinΘR = 1.22 λ/d” mean?

Edit. And asking for an explanation 'in a less physics way' may not be the best tactics in a forum dedicated to physics!
 
Last edited:
Steve4Physics said:
What have you done so far? E.g what have you found out ?
What is meant by resolving power?
Why will the dish’s diameter affect the resolving power?
What do the symbols in the formula “sinΘR = 1.22 λ/d” mean?

Edit. And asking for an explanation 'in a less physics way' may not be the best tactics in a forum dedicated to physics!
Thanks for your hints. I have solved it.
 
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My attempt: Initial total M.E = PE of hanging part + PE of part of chain in the tube. I've considered the table as to be at zero of PE. PE of hanging part = ##\frac{1}{2} \frac{m}{l}gh^{2}##. PE of part in the tube = ##\frac{m}{l}(l - h)gh##. Final ME = ##\frac{1}{2}\frac{m}{l}gh^{2}## + ##\frac{1}{2}\frac{m}{l}hv^{2}##. Since Initial ME = Final ME. Therefore, ##\frac{1}{2}\frac{m}{l}hv^{2}## = ##\frac{m}{l}(l-h)gh##. Solving this gives: ## v = \sqrt{2g(l-h)}##. But the answer in the book...

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