Explicit Calculation of Gauss's Law

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SUMMARY

The discussion focuses on the explicit calculation of Gauss's Law for a sphere centered at the origin with radius R, where R is greater than z0. The total electric flux, represented as ϕ, is derived through the surface integral of the electric field E over the sphere's surface area, confirming that ϕ = q/ϵ0. The participant emphasizes the need to integrate in spherical coordinates and correctly identifies the surface area element dA as R² sinθ dϕ dθ, while noting that the electric field E is constant and normal to the surface. The presence of a charge at (0, 0, z0) complicates the scenario, affecting the uniformity of the electric field.

PREREQUISITES
  • Understanding of Gauss's Law
  • Familiarity with surface integrals in spherical coordinates
  • Knowledge of electric field concepts and their mathematical representation
  • Basic calculus skills for performing integrals
NEXT STEPS
  • Study the derivation of Gauss's Law in electrostatics
  • Learn about surface integrals in spherical coordinates
  • Explore the implications of charge placement on electric field uniformity
  • Practice calculating electric flux for different geometries
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Students of electromagnetism, physics educators, and anyone seeking to deepen their understanding of electric fields and Gauss's Law applications.

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Homework Statement



Consider a sphere centered at origin with radius R > z0. By calculating the total flux
ϕ = ∫E . da through the sphere, explicitly show that ϕ = q/ϵ0

Homework Equations



Gauss's Law

The Attempt at a Solution



I have a general idea of what to do, but I just want to make sure I don't screw up from the start. I think that I have to do a surface integral. The instructions say to integrate over spherical coordinates.

I'm just confused because I usually think of spherical coordinates as 3 dimensions, but a surface integral is 2-D.

I figured that I would change dA into r^2 sinθ dr dϕ dθ, and integrate from there.
I'd use 0 to R for radius, 0 to 2∏ for ϕ, and 0 to pi for θ. I figure you can take E out of the integral because it is constant and always normal to the Surface Area.

Am I on the right track with this one?
 
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Oh yeah, I should probably mention this too. It goes w/o saying, but there is a charge located at (0, 0, z0) as the initial condition.
 
dA=R^2 sinθ dϕ dθ. You don't integrate over r. It's just a surface. And dA should also include the outward pointing unit normal which you need to dot with E. Finally, it doesn't quite go without saying but if the charge is located at (0,0,z0) instead of the origin then the magnitude of the E field isn't constant either. There is some work to do here.
 

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