Explicit Formula for Sum of Series with Fractional Terms

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Homework Help Overview

The original poster attempts to find an explicit formula for the sum of a series defined by the term \(\frac{1}{2n(n+3)}\). The discussion revolves around the convergence and manipulation of this series.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Some participants suggest using partial fractions as a method to analyze the series. Others question the convergence of the series and discuss the implications of separating terms.

Discussion Status

Participants are actively engaging with the problem, exploring different interpretations of convergence and the effectiveness of partial fractions. There is a recognition of the potential for cancellation among terms, indicating a productive direction in the discussion.

Contextual Notes

There is some uncertainty regarding the convergence of the series and the interpretation of the partial fractions approach. Participants are clarifying their understanding of these concepts in relation to the original problem.

Andy111
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Homework Statement



Find an explicit formula for the sum of the series, given that the formula for any term in the series is [tex]\frac{1}{2n(n+3)}[/tex]

Homework Equations





The Attempt at a Solution

 
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Try splitting it into partial fractions and see if that takes you anywhere.
 
rock.freak667 said:
Try splitting it into partial fractions and see if that takes you anywhere.

That'll diverge, won't it? :confused:
 
tiny-tim said:
That'll diverge, won't it? :confused:

It's similar to 1/n^2. That's a p series with p=2. It converges.
 
tiny-tim said:
That'll diverge, won't it? :confused:
I'm not sure what you mean by that, since you said this, not in response to the initial post, but in response to the suggestion to use partial fractions to split it into to parts.

Perhaps you meant that the two parts would each diverge separately. But that's not the point- you don't want to look at them separately- you want to see if there are terms at one point that will cancel terms at another point. In fact, partial fractions works nicely.
 
HallsofIvy said:
… Perhaps you meant that the two parts would each diverge separately. But that's not the point- you don't want to look at them separately- you want to see if there are terms at one point that will cancel terms at another point. In fact, partial fractions works nicely.

oh yes … so it does … isn't that nice!

thanks, HallsofIvy! :smile:
 

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