Exploring Energy Levels and Electron Configurations in Atomic Models

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SUMMARY

The discussion focuses on the electron configurations in atomic models, specifically addressing the distribution of electrons across different shells and sub-shells. The K, L, M, and N shells correspond to electron capacities of 2, 8, 18, and 32, respectively, based on their sub-shell compositions: s (2), p (6), d (10), and f (14). The inquiry also highlights the energy dynamics of electrons in outer shells, noting that electrons in the outermost shell require less energy to remove despite being farther from the nucleus.

PREREQUISITES
  • Understanding of atomic structure and electron shells
  • Familiarity with quantum numbers and their significance
  • Knowledge of sub-shell types: s, p, d, f
  • Basic principles of electron energy levels
NEXT STEPS
  • Research the Pauli Exclusion Principle and its impact on electron configurations
  • Learn about the Aufbau principle for filling electron shells
  • Explore Hund's Rule in relation to electron distribution in sub-shells
  • Investigate the relationship between electron energy levels and ionization energy
USEFUL FOR

Students of chemistry, educators teaching atomic theory, and anyone interested in the principles of electron configurations and energy levels in atomic models.

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Hello, why in the normal atomic configuration every layer except the second can contain only up to 8 electrons if for example the level with quantic number 3 contain up to 18 electrons?
What relation is there between this two models?

Thank you!
 
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You have the K,L,M,N (and so on) shells, which contain 2,8,18,32.. electrons.

Those numbers come from the sub-shells which make up the shells, which are denoted s,p,d,f.
The sub-shells contain 2, 6, 10, 14 electrons, respectively. (twice the odd numbers 1,3,5,7)

The K shell contains only an s sub-shell, so it has two electrons in total. The L shell has one s and one p, giving 2+6=8 electrons in total.
The M shell has an s,p and d, so 2+6+10 = 18, and the N shell has an f sub-shell as well, so 2+6+10+14 = 32 electrons.
 
An electron in the last layer require less energy to be removed, so why the last layer has more energy than the layer nearest the nucleum?
 

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