Does -e^(-infinity) Equal 0 in Mathematics?

Thread starter gillgill
Start date Oct 22, 2005

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The discussion centers on whether -e^(-infinity) equals 0 in mathematics. It is clarified that the limit of e^x as x approaches negative infinity is indeed 0. The expression -e^(-x) is also examined, confirming that as x approaches infinity, the limit is -0, which is equivalent to 0. This leads to the conclusion that -e^(-infinity) does equal 0. Overall, the mathematical consensus is that the limit approaches zero.

Oct 22, 2005

gillgill

does -e^(-infinity) equals 0?

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Oct 22, 2005

Kamataat

The limit of e^x as x-->-infinity is 0.

Oct 22, 2005

hypermorphism

Are you referring to \lim_{x\rightarrow\infty} -e^{-x} ?

Oct 22, 2005

gillgill

yes...

Oct 22, 2005

HallsofIvy

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As kamataat said, \lim_{x\rightarrow\infty} e^{-x}= 0 and so
\lim_{x\rightarrow\infty} -e^{-x}= -0= 0.

Oct 22, 2005

gillgill

i see. thanks.

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