Undergrad Why Are Electric Field Components Ex and Ey Zero in Wave Equation Solutions?

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The discussion centers on the characteristics of electric field components in wave equations, specifically why Ex and Ey are zero when propagation occurs solely along the z-axis. It explains that in a plane wave, the electric and magnetic fields are perpendicular to each other and to the direction of propagation, leading to the conclusion that variations only occur in the direction of propagation. The derivatives ∂Ex/∂x and ∂Ey/∂y are zero because these components do not change in the transverse direction, defining the uniformity of plane waves. If Ex and Ey were not zero, it would contradict the nature of plane waves, which would result in no wave propagation. Understanding these principles is crucial for grasping the behavior of electromagnetic waves.
dyn
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Hi.
I'm following the "derivation" in some lecture notes which shows that the Electric and Magnetic fields are perpendicular to each other and to the direction of propagation. There are 2 points I don't understand

A solution to the wave equation for E-fields is given as E = E0 exp i(ωt-kz).
It then states that if the propagation is along z only then ∂/∂x and ∂/∂y of any property is zero. Why is this so ?

Using Gauss's law this then leads to ∂Ez/∂z = 0 which implies Ez is a constant which is set to zero. But we also have ∂Ex/∂x = 0 and ∂Ey/∂y = 0 so why aren't Ex and Ey equal to a constant which can be set to zero ? I realize this would give no wave.
Thanks
 
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dyn said:
It then states that if the propagation is along z only then ∂/∂x and ∂/∂y of any property is zero. Why is this so ?
That is what defines a plane wave. They vary only along the direction of propagation, and they are uniform in the plane normal to that direction. Not all waves behave this way, but those that do are called plane waves.
 
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