Explosive separation with conservation of momentum and energy

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SUMMARY

The discussion centers on an 8.20-kg object sliding at 2.34 m/s that undergoes an internal explosion, resulting in two equal chunks and an addition of 16 J of kinetic energy. The average acceleration of the chunks is to be calculated over a 0.16-second interval. The key equations derived include mass conservation, momentum conservation, and kinetic energy change, leading to a system of six equations with six unknowns. The simplification arises from recognizing that the two chunks have equal mass, which significantly aids in solving the equations.

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Homework Statement


An 8.20-kg object is sliding across the ice at 2.34 m/s. An internal explosion occurs, splitting the object into two equal chunks and adding 16 J of kinetic energy to the system. What is the average acceleration of the two chunks if the explosive separation takes place over a 0.16-s time interval?

Homework Equations


Let M=8.2 kg be the mass of the object before the explosion.
Let the mass of the two pieces after explosion be m_1,\quad m_2
Let their velocities be v_1,\quad v_2
Let their accelerations be a_1,\quad a_2
Work in cm frame, so initial kinetic energy is zero.
change in kinetic energy is still 16 J.

The Attempt at a Solution


I get six equations with six unknowns, but I can't solve them!

(1) m_1+ m_2 = M
(2) \frac {a_1}{a_2}=- \frac{m_1}{m_2}
(3) 0=m_1v_1+m_2v_2
(4) \Delta K=\frac12m_1v_1^2+\frac12m_2v_2^2
(5) v_1=a_1t
(6) v_2=a_2t
 
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"two equal chunks" - they have the same mass, that simplifies the equations a lot.
 
Duh! thanks...
 

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